Zane had 70% fewer caramel apples than Cole. After Cole gave 400 caramel apples to Zane, Zane had
45 as many caramel apples as Cole. How many caramel apples did each of them have in the end?
- Cole
- Zane
|
Zane |
Cole |
Total |
Before |
3x9 = 27 u |
10x9 = 90 u |
13x9 = 117 u |
Change |
+ 400 |
- 400 |
|
After |
4x13 = 52 u |
5x13 = 65 u |
9x13 = 117 u |
Number of caramel apples that Zane had at first in percentage
= 100% - 70%
= 30%
30% =
30100 =
310 The total number of caramel apples at first and in the end remains unchanged. Make the total number of caramel apples the same. LCM of 9 and 13 is 117.
Number of caramel apples that Cole gave to Zane
= 90 u - 65 u
= 25 u
25 u = 400
1 u = 400 ÷ 25 = 16
Number of caramel apples that Zane had in the end
= 52 u
= 52 x 16
= 832
Number of caramel apples that Cole had in the end
= 65 u
= 65 x 16
= 1040
Answer(s): (a) 832; (b) 1040