Simon had 60% fewer lollipops than Riordan. After Riordan gave 216 lollipops to Simon, Simon had ²₃ as many lollipops as Riordan. How many lollipops did each of them have in the end?

1. Riordan
2. Simon

	Simon	Riordan	Total
Before	2x5 = 10 u	5x5 = 25 u	7x5 = 35 u
Change	+ 216	- 216
After	2x7 = 14 u	3x7 =  21 u	5x7 = 35 u

Number of lollipops that Simon had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of lollipops at first and in the end remains unchanged. Make the total number of lollipops the same. LCM of 5 and 7 is 35.

Number of lollipops that Riordan gave to Simon
= 25 u - 21 u
= 4 u

4 u = 216

1 u = 216 ÷ 4 = 54

Number of lollipops that Simon had in the end
= 14 u
= 14 x 54
= 756

Number of lollipops that Riordan had in the end
= 21 u
= 21 x 54
= 1134

Answer(s): (a) 756; (b) 1134