Riordan had 65% fewer chocolate bars than Reggie. After Reggie gave 266 chocolate bars to Riordan, Riordan had ²₃ as many chocolate bars as Reggie. How many chocolate bars did each of them have in the end?

1. Reggie
2. Riordan

	Riordan	Reggie	Total
Before	7x5 = 35 u	20x5 = 100 u	27x5 = 135 u
Change	+ 266	- 266
After	2x27 = 54 u	3x27 =  81 u	5x27 = 135 u

Number of chocolate bars that Riordan had at first in percentage
= 100% - 65%
= 35%

35% = ³⁵₁₀₀ = ⁷₂₀

The total number of chocolate bars at first and in the end remains unchanged. Make the total number of chocolate bars the same. LCM of 5 and 27 is 135.

Number of chocolate bars that Reggie gave to Riordan
= 100 u - 81 u
= 19 u

19 u = 266

1 u = 266 ÷ 19 = 14

Number of chocolate bars that Riordan had in the end
= 54 u
= 54 x 14
= 756

Number of chocolate bars that Reggie had in the end
= 81 u
= 81 x 14
= 1134

Answer(s): (a) 756; (b) 1134