Julian had 85% fewer candy canes than Gabriel. After Gabriel gave 248 candy canes to Julian, Julian had ²₃ as many candy canes as Gabriel. How many candy canes did each of them have in the end?

1. Gabriel
2. Julian

	Julian	Gabriel	Total
Before	3x5 = 15 u	20x5 = 100 u	23x5 = 115 u
Change	+ 248	- 248
After	2x23 = 46 u	3x23 =  69 u	5x23 = 115 u

Number of candy canes that Julian had at first in percentage
= 100% - 85%
= 15%

15% = ¹⁵₁₀₀ = ³₂₀

The total number of candy canes at first and in the end remains unchanged. Make the total number of candy canes the same. LCM of 5 and 23 is 115.

Number of candy canes that Gabriel gave to Julian
= 100 u - 69 u
= 31 u

31 u = 248

1 u = 248 ÷ 31 = 8

Number of candy canes that Julian had in the end
= 46 u
= 46 x 8
= 368

Number of candy canes that Gabriel had in the end
= 69 u
= 69 x 8
= 552

Answer(s): (a) 368; (b) 552