Tommy had 75% fewer candy canes than Riordan. After Riordan gave 154 candy canes to Tommy, Tommy had
56 as many candy canes as Riordan. How many candy canes did each of them have in the end?
- Riordan
- Tommy
|
Tommy |
Riordan |
Total |
Before |
1x11 = 11 u |
4x11 = 44 u |
5x11 = 55 u |
Change |
+ 154 |
- 154 |
|
After |
5x5 = 25 u |
6x5 = 30 u |
11x5 = 55 u |
Number of candy canes that Tommy had at first in percentage
= 100% - 75%
= 25%
25% =
25100 =
14 The total number of candy canes at first and in the end remains unchanged. Make the total number of candy canes the same. LCM of 11 and 5 is 55.
Number of candy canes that Riordan gave to Tommy
= 44 u - 30 u
= 14 u
14 u = 154
1 u = 154 ÷ 14 = 11
Number of candy canes that Tommy had in the end
= 25 u
= 25 x 11
= 275
Number of candy canes that Riordan had in the end
= 30 u
= 30 x 11
= 330
Answer(s): (a) 275; (b) 330