Perry had 60% fewer sweets than Sam. After Sam gave 238 sweets to Perry, Perry had
34 as many sweets as Sam. How many sweets did each of them have in the end?
- Sam
- Perry
| |
Perry |
Sam |
Total |
| Before |
2x7 =
14 u |
5x7 =
35 u |
7x7 =
49 u |
| Change |
+ 238 |
- 238 |
|
| After |
3x7 =
21 u |
4x7 =
28 u |
7x7 =
49 u |
Number of sweets that Perry had at first in percentage
= 100% - 60%
= 40%
40% =
40100 =
25 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 7 and 7 is 49.
Number of sweets that Sam gave to Perry
= 35 u - 28 u
= 7 u
7 u = 238
1 u = 238 ÷ 7 = 34
Number of sweets that Perry had in the end
= 21 u
= 21 x 34
= 714
Number of sweets that Sam had in the end
= 28 u
= 28 x 34
= 952
Answer(s): (a) 714; (b) 952
