Bryan had 75% fewer chocolate bars than Brandon. After Brandon gave 400 chocolate bars to Bryan, Bryan had ³₄ as many chocolate bars as Brandon. How many chocolate bars did each of them have in the end?

1. Brandon
2. Bryan

	Bryan	Brandon	Total
Before	1x7 = 7 u	4x7 = 28 u	5x7 = 35 u
Change	+ 400	- 400
After	3x5 = 15 u	4x5 =  20 u	7x5 = 35 u

Number of chocolate bars that Bryan had at first in percentage
= 100% - 75%
= 25%

25% = ²⁵₁₀₀ = ¹₄

The total number of chocolate bars at first and in the end remains unchanged. Make the total number of chocolate bars the same. LCM of 7 and 5 is 35.

Number of chocolate bars that Brandon gave to Bryan
= 28 u - 20 u
= 8 u

8 u = 400

1 u = 400 ÷ 8 = 50

Number of chocolate bars that Bryan had in the end
= 15 u
= 15 x 50
= 750

Number of chocolate bars that Brandon had in the end
= 20 u
= 20 x 50
= 1000

Answer(s): (a) 750; (b) 1000