Andy had 60% fewer sweets than Ethan. After Ethan gave 224 sweets to Andy, Andy had
34 as many sweets as Ethan. How many sweets did each of them have in the end?
- Ethan
- Andy
| |
Andy |
Ethan |
Total |
| Before |
2x7 =
14 u |
5x7 =
35 u |
7x7 =
49 u |
| Change |
+ 224 |
- 224 |
|
| After |
3x7 =
21 u |
4x7 =
28 u |
7x7 =
49 u |
Number of sweets that Andy had at first in percentage
= 100% - 60%
= 40%
40% =
40100 =
25 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 7 and 7 is 49.
Number of sweets that Ethan gave to Andy
= 35 u - 28 u
= 7 u
7 u = 224
1 u = 224 ÷ 7 = 32
Number of sweets that Andy had in the end
= 21 u
= 21 x 32
= 672
Number of sweets that Ethan had in the end
= 28 u
= 28 x 32
= 896
Answer(s): (a) 672; (b) 896
