Zeph had 75% fewer sweets than Vaidev. After Vaidev gave 168 sweets to Zeph, Zeph had
56 as many sweets as Vaidev. How many sweets did each of them have in the end?
- Vaidev
- Zeph
|
Zeph |
Vaidev |
Total |
Before |
1x11 = 11 u |
4x11 = 44 u |
5x11 = 55 u |
Change |
+ 168 |
- 168 |
|
After |
5x5 = 25 u |
6x5 = 30 u |
11x5 = 55 u |
Number of sweets that Zeph had at first in percentage
= 100% - 75%
= 25%
25% =
25100 =
14 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 11 and 5 is 55.
Number of sweets that Vaidev gave to Zeph
= 44 u - 30 u
= 14 u
14 u = 168
1 u = 168 ÷ 14 = 12
Number of sweets that Zeph had in the end
= 25 u
= 25 x 12
= 300
Number of sweets that Vaidev had in the end
= 30 u
= 30 x 12
= 360
Answer(s): (a) 300; (b) 360