George had 60% fewer lollipops than Lee. After Lee gave 325 lollipops to George, George had
56 as many lollipops as Lee. How many lollipops did each of them have in the end?
- Lee
- George
| |
George |
Lee |
Total |
| Before |
2x11 =
22 u |
5x11 =
55 u |
7x11 =
77 u |
| Change |
+ 325 |
- 325 |
|
| After |
5x7 =
35 u |
6x7 =
42 u |
11x7 =
77 u |
Number of lollipops that George had at first in percentage
= 100% - 60%
= 40%
40% =
40100 =
25 The total number of lollipops at first and in the end remains unchanged. Make the total number of lollipops the same. LCM of 11 and 7 is 77.
Number of lollipops that Lee gave to George
= 55 u - 42 u
= 13 u
13 u = 325
1 u = 325 ÷ 13 = 25
Number of lollipops that George had in the end
= 35 u
= 35 x 25
= 875
Number of lollipops that Lee had in the end
= 42 u
= 42 x 25
= 1050
Answer(s): (a) 875; (b) 1050
