Liam had 80% fewer sweets than Harry. After Harry gave 176 sweets to Liam, Liam had
34 as many sweets as Harry. How many sweets did each of them have in the end?
- Harry
- Liam
| |
Liam |
Harry |
Total |
| Before |
1x7 =
7 u |
5x7 =
35 u |
6x7 =
42 u |
| Change |
+ 176 |
- 176 |
|
| After |
3x6 =
18 u |
4x6 =
24 u |
7x6 =
42 u |
Number of sweets that Liam had at first in percentage
= 100% - 80%
= 20%
20% =
20100 =
15 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 7 and 6 is 42.
Number of sweets that Harry gave to Liam
= 35 u - 24 u
= 11 u
11 u = 176
1 u = 176 ÷ 11 = 16
Number of sweets that Liam had in the end
= 18 u
= 18 x 16
= 288
Number of sweets that Harry had in the end
= 24 u
= 24 x 16
= 384
Answer(s): (a) 288; (b) 384
