Neave had 60% fewer mochi balls than Oscar. After Oscar gave 336 mochi balls to Neave, Neave had ²₃ as many mochi balls as Oscar. How many mochi balls did each of them have in the end?

1. Oscar
2. Neave

	Neave	Oscar	Total
Before	2x5 = 10 u	5x5 = 25 u	7x5 = 35 u
Change	+ 336	- 336
After	2x7 = 14 u	3x7 =  21 u	5x7 = 35 u

Number of mochi balls that Neave had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of mochi balls at first and in the end remains unchanged. Make the total number of mochi balls the same. LCM of 5 and 7 is 35.

Number of mochi balls that Oscar gave to Neave
= 25 u - 21 u
= 4 u

4 u = 336

1 u = 336 ÷ 4 = 84

Number of mochi balls that Neave had in the end
= 14 u
= 14 x 84
= 1176

Number of mochi balls that Oscar had in the end
= 21 u
= 21 x 84
= 1764

Answer(s): (a) 1176; (b) 1764