Paul had 70% fewer mochi balls than Pierre. After Pierre gave 234 mochi balls to Paul, Paul had ³₄ as many mochi balls as Pierre. How many mochi balls did each of them have in the end?

1. Pierre
2. Paul

	Paul	Pierre	Total
Before	3x7 = 21 u	10x7 = 70 u	13x7 = 91 u
Change	+ 234	- 234
After	3x13 = 39 u	4x13 =  52 u	7x13 = 91 u

Number of mochi balls that Paul had at first in percentage
= 100% - 70%
= 30%

30% = ³⁰₁₀₀ = ³₁₀

The total number of mochi balls at first and in the end remains unchanged. Make the total number of mochi balls the same. LCM of 7 and 13 is 91.

Number of mochi balls that Pierre gave to Paul
= 70 u - 52 u
= 18 u

18 u = 234

1 u = 234 ÷ 18 = 13

Number of mochi balls that Paul had in the end
= 39 u
= 39 x 13
= 507

Number of mochi balls that Pierre had in the end
= 52 u
= 52 x 13
= 676

Answer(s): (a) 507; (b) 676