Wesley had 80% fewer sweets than Tim. After Tim gave 287 sweets to Wesley, Wesley had
23 as many sweets as Tim. How many sweets did each of them have in the end?
- Tim
- Wesley
| |
Wesley |
Tim |
Total |
| Before |
1x5 =
5 u |
5x5 =
25 u |
6x5 =
30 u |
| Change |
+ 287 |
- 287 |
|
| After |
2x6 =
12 u |
3x6 =
18 u |
5x6 =
30 u |
Number of sweets that Wesley had at first in percentage
= 100% - 80%
= 20%
20% =
20100 =
15 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 5 and 6 is 30.
Number of sweets that Tim gave to Wesley
= 25 u - 18 u
= 7 u
7 u = 287
1 u = 287 ÷ 7 = 41
Number of sweets that Wesley had in the end
= 12 u
= 12 x 41
= 492
Number of sweets that Tim had in the end
= 18 u
= 18 x 41
= 738
Answer(s): (a) 492; (b) 738
