Caden had 75% fewer chocolate bars than Michael. After Michael gave 300 chocolate bars to Caden, Caden had ²₃ as many chocolate bars as Michael. How many chocolate bars did each of them have in the end?

1. Michael
2. Caden

	Caden	Michael	Total
Before	1x5 = 5 u	4x5 = 20 u	5x5 = 25 u
Change	+ 300	- 300
After	2x5 = 10 u	3x5 =  15 u	5x5 = 25 u

Number of chocolate bars that Caden had at first in percentage
= 100% - 75%
= 25%

25% = ²⁵₁₀₀ = ¹₄

The total number of chocolate bars at first and in the end remains unchanged. Make the total number of chocolate bars the same. LCM of 5 and 5 is 25.

Number of chocolate bars that Michael gave to Caden
= 20 u - 15 u
= 5 u

5 u = 300

1 u = 300 ÷ 5 = 60

Number of chocolate bars that Caden had in the end
= 10 u
= 10 x 60
= 600

Number of chocolate bars that Michael had in the end
= 15 u
= 15 x 60
= 900

Answer(s): (a) 600; (b) 900