Xavier had 75% fewer lollipops than Flynn. After Flynn gave 275 lollipops to Xavier, Xavier had ²₃ as many lollipops as Flynn. How many lollipops did each of them have in the end?

1. Flynn
2. Xavier

	Xavier	Flynn	Total
Before	1x5 = 5 u	4x5 = 20 u	5x5 = 25 u
Change	+ 275	- 275
After	2x5 = 10 u	3x5 =  15 u	5x5 = 25 u

Number of lollipops that Xavier had at first in percentage
= 100% - 75%
= 25%

25% = ²⁵₁₀₀ = ¹₄

The total number of lollipops at first and in the end remains unchanged. Make the total number of lollipops the same. LCM of 5 and 5 is 25.

Number of lollipops that Flynn gave to Xavier
= 20 u - 15 u
= 5 u

5 u = 275

1 u = 275 ÷ 5 = 55

Number of lollipops that Xavier had in the end
= 10 u
= 10 x 55
= 550

Number of lollipops that Flynn had in the end
= 15 u
= 15 x 55
= 825

Answer(s): (a) 550; (b) 825