Howard had 80% fewer chocolate bars than Warren. After Warren gave 380 chocolate bars to Howard, Howard had ⁵₆ as many chocolate bars as Warren. How many chocolate bars did each of them have in the end?

1. Warren
2. Howard

	Howard	Warren	Total
Before	1x11 = 11 u	5x11 = 55 u	6x11 = 66 u
Change	+ 380	- 380
After	5x6 = 30 u	6x6 =  36 u	11x6 = 66 u

Number of chocolate bars that Howard had at first in percentage
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

The total number of chocolate bars at first and in the end remains unchanged. Make the total number of chocolate bars the same. LCM of 11 and 6 is 66.

Number of chocolate bars that Warren gave to Howard
= 55 u - 36 u
= 19 u

19 u = 380

1 u = 380 ÷ 19 = 20

Number of chocolate bars that Howard had in the end
= 30 u
= 30 x 20
= 600

Number of chocolate bars that Warren had in the end
= 36 u
= 36 x 20
= 720

Answer(s): (a) 600; (b) 720