Archie had three bags of ground pepper, V, W and X and the mass of each bag of ground pepper was in the ratio 4 : 1 : 1. Archie decided to transfer 40% of ground pepper from Bag V into Bag W and 70% of ground pepper from Bag X into Bag W. Given that the mass of Bag W was 26.4 kg in the end, how many kilograms of ground pepper were transferred into Bag W?
|
V |
W |
X |
Before |
4 u |
1 u |
1 u |
Change 1 |
- 1.6 u |
+ 1.6 u |
|
Change 2 |
|
+ 0.7 u |
- 0.7 u |
After |
2.4 u |
3.3 u |
0.3 u |
Mass of ground pepper transferred from Bag V into Bag W
= 40% x 4 u
=
40100 x 4 u
= 2.4 u
Mass of ground pepper transferred from Bag X into Bag W
= 70% x 1 u
=
70100 x 1 u
= 0.7 u
Mass of ground pepper in Bag W in the end
= 1 u + 1.6 u + 0.7 u
= 3.3 u
3.3 u = 26.4
1 u = 26.4 ÷ 3.3 = 8
Mass of ground pepper transferred into Bag W
= 1.6 u + 0.7 u
= 2.3 u
= 2.3 x 8
= 18.4 kg
Answer(s): 18.4 kg