Carl had three bags of ground pepper, W, X and Y and the mass of each bag of ground pepper was in the ratio 5 : 2 : 5. Carl decided to transfer 20% of ground pepper from Bag W into Bag X and 60% of ground pepper from Bag Y into Bag X. Given that the mass of Bag X was 12 kg in the end, how many kilograms of ground pepper were transferred into Bag X?
|
W |
X |
Y |
Before |
5 u |
2 u |
5 u |
Change 1 |
- 1 u |
+ 1 u |
|
Change 2 |
|
+ 3 u |
- 3 u |
After |
4 u |
6 u |
2 u |
Mass of ground pepper transferred from Bag W into Bag X
= 20% x 5 u
=
20100 x 5 u
= 4 u
Mass of ground pepper transferred from Bag Y into Bag X
= 60% x 5 u
=
60100 x 5 u
= 3 u
Mass of ground pepper in Bag X in the end
= 2 u + 1 u + 3 u
= 6 u
6 u = 12
1 u = 12 ÷ 6 = 2
Mass of ground pepper transferred into Bag X
= 1 u + 3 u
= 4 u
= 4 x 2
= 8 kg
Answer(s): 8 kg