Mark had three bags of peppercorns, S, T and U and the mass of each bag of peppercorns was in the ratio 1 : 2 : 2. Mark decided to transfer 30% of peppercorns from Bag S into Bag T and 80% of peppercorns from Bag U into Bag T. Given that the mass of Bag T was 35.1 kg in the end, how many kilograms of peppercorns were transferred into Bag T?

	S	T	U
Before	1 u	2 u	2 u
Change 1	- 0.3 u	+ 0.3 u
Change 2		+ 1.6 u	- 1.6 u
After	0.7 u	3.9 u	0.4 u

Mass of peppercorns transferred from Bag S into Bag T
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.7 u

Mass of peppercorns transferred from Bag U into Bag T
= 80% x 2 u
= ⁸⁰₁₀₀ x 2 u
= 1.6 u

Mass of peppercorns in Bag T in the end
= 2 u + 0.3 u + 1.6 u
= 3.9 u

3.9 u = 35.1 

1 u = 35.1 ÷ 3.9 = 9

Mass of peppercorns transferred into Bag T
= 0.3 u + 1.6 u
= 1.9 u
= 1.9 x 9
= 17.1 kg

Answer(s): 17.1 kg