Riordan had three bags of brown rice, G, H and J and the mass of each bag of brown rice was in the ratio 5 : 3 : 3. Riordan decided to transfer 20% of brown rice from Bag G into Bag H and 90% of brown rice from Bag J into Bag H. Given that the mass of Bag H was 60.3 kg in the end, how many kilograms of brown rice were transferred into Bag H?

	G	H	J
Before	5 u	3 u	3 u
Change 1	- 1 u	+ 1 u
Change 2		+ 2.7 u	- 2.7 u
After	4 u	6.7 u	0.3 u

Mass of brown rice transferred from Bag G into Bag H
= 20% x 5 u
= ²⁰₁₀₀ x 5 u
= 4 u

Mass of brown rice transferred from Bag J into Bag H
= 90% x 3 u
= ⁹⁰₁₀₀ x 3 u
= 2.7 u

Mass of brown rice in Bag H in the end
= 3 u + 1 u + 2.7 u
= 6.7 u

6.7 u = 60.3 

1 u = 60.3 ÷ 6.7 = 9

Mass of brown rice transferred into Bag H
= 1 u + 2.7 u
= 3.7 u
= 3.7 x 9
= 33.3 kg

Answer(s): 33.3 kg