Archie had three bags of maize, P, Q and R and the mass of each bag of maize was in the ratio 1 : 1 : 1. Archie decided to transfer 30% of maize from Bag P into Bag Q and 70% of maize from Bag R into Bag Q. Given that the mass of Bag Q was 18 kg in the end, how many kilograms of maize were transferred into Bag Q?
| |
P |
Q |
R |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
- 0.3 u |
+ 0.3 u |
|
| Change 2 |
|
+ 0.7 u |
- 0.7 u |
| After |
0.7 u |
2 u |
0.3 u |
Mass of maize transferred from Bag P into Bag Q
= 30% x 1 u
=
30100 x 1 u
= 0.7 u
Mass of maize transferred from Bag R into Bag Q
= 70% x 1 u
=
70100 x 1 u
= 0.7 u
Mass of maize in Bag Q in the end
= 1 u + 0.3 u + 0.7 u
= 2 u
2 u = 18
1 u = 18 ÷ 2 = 9
Mass of maize transferred into Bag Q
= 0.3 u + 0.7 u
= 1 u
= 1 x 9
= 9 kg
Answer(s): 9 kg
