John had three bags of corn starch, V, W and X and the mass of each bag of corn starch was in the ratio 2 : 3 : 4. John decided to transfer 10% of corn starch from Bag V into Bag W and 60% of corn starch from Bag X into Bag W. Given that the mass of Bag W was 50.4 kg in the end, how many kilograms of corn starch were transferred into Bag W?

	V	W	X
Before	2 u	3 u	4 u
Change 1	- 0.2 u	+ 0.2 u
Change 2		+ 2.4 u	- 2.4 u
After	1.8 u	5.6 u	1.6 u

Mass of corn starch transferred from Bag V into Bag W
= 10% x 2 u
= ¹⁰₁₀₀ x 2 u
= 1.8 u

Mass of corn starch transferred from Bag X into Bag W
= 60% x 4 u
= ⁶⁰₁₀₀ x 4 u
= 2.4 u

Mass of corn starch in Bag W in the end
= 3 u + 0.2 u + 2.4 u
= 5.6 u

5.6 u = 50.4 

1 u = 50.4 ÷ 5.6 = 9

Mass of corn starch transferred into Bag W
= 0.2 u + 2.4 u
= 2.6 u
= 2.6 x 9
= 23.4 kg

Answer(s): 23.4 kg