Albert had three bags of barley, F, G and H and the mass of each bag of barley was in the ratio 2 : 4 : 3. Albert decided to transfer 40% of barley from Bag F into Bag G and 60% of barley from Bag H into Bag G. Given that the mass of Bag G was 19.8 kg in the end, how many kilograms of barley were transferred into Bag G?

	F	G	H
Before	2 u	4 u	3 u
Change 1	- 0.8 u	+ 0.8 u
Change 2		+ 1.8 u	- 1.8 u
After	1.2 u	6.6 u	1.2 u

Mass of barley transferred from Bag F into Bag G
= 40% x 2 u
= ⁴⁰₁₀₀ x 2 u
= 1.2 u

Mass of barley transferred from Bag H into Bag G
= 60% x 3 u
= ⁶⁰₁₀₀ x 3 u
= 1.8 u

Mass of barley in Bag G in the end
= 4 u + 0.8 u + 1.8 u
= 6.6 u

6.6 u = 19.8 

1 u = 19.8 ÷ 6.6 = 3

Mass of barley transferred into Bag G
= 0.8 u + 1.8 u
= 2.6 u
= 2.6 x 3
= 7.8 kg

Answer(s): 7.8 kg