George had three bags of soya beans, E, F and G and the mass of each bag of soya beans was in the ratio 2 : 5 : 3. George decided to transfer 30% of soya beans from Bag E into Bag F and 70% of soya beans from Bag G into Bag F. Given that the mass of Bag F was 69.3 kg in the end, how many kilograms of soya beans were transferred into Bag F?

	E	F	G
Before	2 u	5 u	3 u
Change 1	- 0.6 u	+ 0.6 u
Change 2		+ 2.1 u	- 2.1 u
After	1.4 u	7.7 u	0.9 u

Mass of soya beans transferred from Bag E into Bag F
= 30% x 2 u
= ³⁰₁₀₀ x 2 u
= 1.4 u

Mass of soya beans transferred from Bag G into Bag F
= 70% x 3 u
= ⁷⁰₁₀₀ x 3 u
= 2.1 u

Mass of soya beans in Bag F in the end
= 5 u + 0.6 u + 2.1 u
= 7.7 u

7.7 u = 69.3 

1 u = 69.3 ÷ 7.7 = 9

Mass of soya beans transferred into Bag F
= 0.6 u + 2.1 u
= 2.7 u
= 2.7 x 9
= 24.3 kg

Answer(s): 24.3 kg