Reggie had three bags of brown rice, T, U and V and the mass of each bag of brown rice was in the ratio 1 : 3 : 2. Reggie decided to transfer 20% of brown rice from Bag T into Bag U and 80% of brown rice from Bag V into Bag U. Given that the mass of Bag U was 9.6 kg in the end, how many kilograms of brown rice were transferred into Bag U?

	T	U	V
Before	1 u	3 u	2 u
Change 1	- 0.2 u	+ 0.2 u
Change 2		+ 1.6 u	- 1.6 u
After	0.8 u	4.8 u	0.4 u

Mass of brown rice transferred from Bag T into Bag U
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.8 u

Mass of brown rice transferred from Bag V into Bag U
= 80% x 2 u
= ⁸⁰₁₀₀ x 2 u
= 1.6 u

Mass of brown rice in Bag U in the end
= 3 u + 0.2 u + 1.6 u
= 4.8 u

4.8 u = 9.6 

1 u = 9.6 ÷ 4.8 = 2

Mass of brown rice transferred into Bag U
= 0.2 u + 1.6 u
= 1.8 u
= 1.8 x 2
= 3.6 kg

Answer(s): 3.6 kg