Seth had three bags of corn starch, X, Y and Z and the mass of each bag of corn starch was in the ratio 5 : 1 : 1. Seth decided to transfer 40% of corn starch from Bag X into Bag Y and 60% of corn starch from Bag Z into Bag Y. Given that the mass of Bag Y was 32.4 kg in the end, how many kilograms of corn starch were transferred into Bag Y?

	X	Y	Z
Before	5 u	1 u	1 u
Change 1	- 2 u	+ 2 u
Change 2		+ 0.6 u	- 0.6 u
After	3 u	3.6 u	0.4 u

Mass of corn starch transferred from Bag X into Bag Y
= 40% x 5 u
= ⁴⁰₁₀₀ x 5 u
= 3 u

Mass of corn starch transferred from Bag Z into Bag Y
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Mass of corn starch in Bag Y in the end
= 1 u + 2 u + 0.6 u
= 3.6 u

3.6 u = 32.4 

1 u = 32.4 ÷ 3.6 = 9

Mass of corn starch transferred into Bag Y
= 2 u + 0.6 u
= 2.6 u
= 2.6 x 9
= 23.4 kg

Answer(s): 23.4 kg