Billy had three bags of brown rice, V, W and X and the mass of each bag of brown rice was in the ratio 3 : 5 : 2. Billy decided to transfer 10% of brown rice from Bag V into Bag W and 90% of brown rice from Bag X into Bag W. Given that the mass of Bag W was 49.7 kg in the end, how many kilograms of brown rice were transferred into Bag W?
|
V |
W |
X |
Before |
3 u |
5 u |
2 u |
Change 1 |
- 0.3 u |
+ 0.3 u |
|
Change 2 |
|
+ 1.8 u |
- 1.8 u |
After |
2.7 u |
7.1 u |
0.2 u |
Mass of brown rice transferred from Bag V into Bag W
= 10% x 3 u
=
10100 x 3 u
= 2.7 u
Mass of brown rice transferred from Bag X into Bag W
= 90% x 2 u
=
90100 x 2 u
= 1.8 u
Mass of brown rice in Bag W in the end
= 5 u + 0.3 u + 1.8 u
= 7.1 u
7.1 u = 49.7
1 u = 49.7 ÷ 7.1 = 7
Mass of brown rice transferred into Bag W
= 0.3 u + 1.8 u
= 2.1 u
= 2.1 x 7
= 14.7 kg
Answer(s): 14.7 kg