Albert had three bags of soya beans, E, F and G and the mass of each bag of soya beans was in the ratio 2 : 1 : 5. Albert decided to transfer 30% of soya beans from Bag E into Bag F and 90% of soya beans from Bag G into Bag F. Given that the mass of Bag F was 12.2 kg in the end, how many kilograms of soya beans were transferred into Bag F?

	E	F	G
Before	2 u	1 u	5 u
Change 1	- 0.6 u	+ 0.6 u
Change 2		+ 4.5 u	- 4.5 u
After	1.4 u	6.1 u	0.5 u

Mass of soya beans transferred from Bag E into Bag F
= 30% x 2 u
= ³⁰₁₀₀ x 2 u
= 1.4 u

Mass of soya beans transferred from Bag G into Bag F
= 90% x 5 u
= ⁹⁰₁₀₀ x 5 u
= 4.5 u

Mass of soya beans in Bag F in the end
= 1 u + 0.6 u + 4.5 u
= 6.1 u

6.1 u = 12.2 

1 u = 12.2 ÷ 6.1 = 2

Mass of soya beans transferred into Bag F
= 0.6 u + 4.5 u
= 5.1 u
= 5.1 x 2
= 10.2 kg

Answer(s): 10.2 kg