Will had three bags of rice, B, C and D and the mass of each bag of rice was in the ratio 2 : 2 : 1. Will decided to transfer 10% of rice from Bag B into Bag C and 70% of rice from Bag D into Bag C. Given that the mass of Bag C was 26.1 kg in the end, how many kilograms of rice were transferred into Bag C?
| |
B |
C |
D |
| Before |
2 u |
2 u |
1 u |
| Change 1 |
- 0.2 u |
+ 0.2 u |
|
| Change 2 |
|
+ 0.7 u |
- 0.7 u |
| After |
1.8 u |
2.9 u |
0.3 u |
Mass of rice transferred from Bag B into Bag C
= 10% x 2 u
=
10100 x 2 u
= 1.8 u
Mass of rice transferred from Bag D into Bag C
= 70% x 1 u
=
70100 x 1 u
= 0.7 u
Mass of rice in Bag C in the end
= 2 u + 0.2 u + 0.7 u
= 2.9 u
2.9 u = 26.1
1 u = 26.1 ÷ 2.9 = 9
Mass of rice transferred into Bag C
= 0.2 u + 0.7 u
= 0.9 u
= 0.9 x 9
= 8.1 kg
Answer(s): 8.1 kg
