Zeph had three bags of barley, G, H and J and the mass of each bag of barley was in the ratio 3 : 5 : 1. Zeph decided to transfer 40% of barley from Bag G into Bag H and 70% of barley from Bag J into Bag H. Given that the mass of Bag H was 34.5 kg in the end, how many kilograms of barley were transferred into Bag H?
| |
G |
H |
J |
| Before |
3 u |
5 u |
1 u |
| Change 1 |
- 1.2 u |
+ 1.2 u |
|
| Change 2 |
|
+ 0.7 u |
- 0.7 u |
| After |
1.8 u |
6.9 u |
0.3 u |
Mass of barley transferred from Bag G into Bag H
= 40% x 3 u
=
40100 x 3 u
= 1.8 u
Mass of barley transferred from Bag J into Bag H
= 70% x 1 u
=
70100 x 1 u
= 0.7 u
Mass of barley in Bag H in the end
= 5 u + 1.2 u + 0.7 u
= 6.9 u
6.9 u = 34.5
1 u = 34.5 ÷ 6.9 = 5
Mass of barley transferred into Bag H
= 1.2 u + 0.7 u
= 1.9 u
= 1.9 x 5
= 9.5 kg
Answer(s): 9.5 kg
