Peter had three bags of peppercorns, C, D and E and the mass of each bag of peppercorns was in the ratio 4 : 4 : 1. Peter decided to transfer 40% of peppercorns from Bag C into Bag D and 70% of peppercorns from Bag E into Bag D. Given that the mass of Bag D was 12.6 kg in the end, how many kilograms of peppercorns were transferred into Bag D?

	C	D	E
Before	4 u	4 u	1 u
Change 1	- 1.6 u	+ 1.6 u
Change 2		+ 0.7 u	- 0.7 u
After	2.4 u	6.3 u	0.3 u

Mass of peppercorns transferred from Bag C into Bag D
= 40% x 4 u
= ⁴⁰₁₀₀ x 4 u
= 2.4 u

Mass of peppercorns transferred from Bag E into Bag D
= 70% x 1 u
= ⁷⁰₁₀₀ x 1 u
= 0.7 u

Mass of peppercorns in Bag D in the end
= 4 u + 1.6 u + 0.7 u
= 6.3 u

6.3 u = 12.6 

1 u = 12.6 ÷ 6.3 = 2

Mass of peppercorns transferred into Bag D
= 1.6 u + 0.7 u
= 2.3 u
= 2.3 x 2
= 4.6 kg

Answer(s): 4.6 kg