Justin had three bags of sesame seeds, E, F and G and the mass of each bag of sesame seeds was in the ratio 2 : 1 : 2. Justin decided to transfer 10% of sesame seeds from Bag E into Bag F and 80% of sesame seeds from Bag G into Bag F. Given that the mass of Bag F was 28 kg in the end, how many kilograms of sesame seeds were transferred into Bag F?

	E	F	G
Before	2 u	1 u	2 u
Change 1	- 0.2 u	+ 0.2 u
Change 2		+ 1.6 u	- 1.6 u
After	1.8 u	2.8 u	0.4 u

Mass of sesame seeds transferred from Bag E into Bag F
= 10% x 2 u
= ¹⁰₁₀₀ x 2 u
= 1.8 u

Mass of sesame seeds transferred from Bag G into Bag F
= 80% x 2 u
= ⁸⁰₁₀₀ x 2 u
= 1.6 u

Mass of sesame seeds in Bag F in the end
= 1 u + 0.2 u + 1.6 u
= 2.8 u

2.8 u = 28 

1 u = 28 ÷ 2.8 = 10

Mass of sesame seeds transferred into Bag F
= 0.2 u + 1.6 u
= 1.8 u
= 1.8 x 10
= 18 kg

Answer(s): 18 kg