Bobby had three bags of ground pepper, E, F and G and the mass of each bag of ground pepper was in the ratio 1 : 1 : 1. Bobby decided to transfer 40% of ground pepper from Bag E into Bag F and 60% of ground pepper from Bag G into Bag F. Given that the mass of Bag F was 16 kg in the end, how many kilograms of ground pepper were transferred into Bag F?

	E	F	G
Before	1 u	1 u	1 u
Change 1	- 0.4 u	+ 0.4 u
Change 2		+ 0.6 u	- 0.6 u
After	0.6 u	2 u	0.4 u

Mass of ground pepper transferred from Bag E into Bag F
= 40% x 1 u
= ⁴⁰₁₀₀ x 1 u
= 0.6 u

Mass of ground pepper transferred from Bag G into Bag F
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Mass of ground pepper in Bag F in the end
= 1 u + 0.4 u + 0.6 u
= 2 u

2 u = 16 

1 u = 16 ÷ 2 = 8

Mass of ground pepper transferred into Bag F
= 0.4 u + 0.6 u
= 1 u
= 1 x 8
= 8 kg

Answer(s): 8 kg