Michael had three bags of ground pepper, T, U and V and the mass of each bag of ground pepper was in the ratio 5 : 4 : 5. Michael decided to transfer 40% of ground pepper from Bag T into Bag U and 70% of ground pepper from Bag V into Bag U. Given that the mass of Bag U was 76 kg in the end, how many kilograms of ground pepper were transferred into Bag U?

	T	U	V
Before	5 u	4 u	5 u
Change 1	- 2 u	+ 2 u
Change 2		+ 3.5 u	- 3.5 u
After	3 u	9.5 u	1.5 u

Mass of ground pepper transferred from Bag T into Bag U
= 40% x 5 u
= ⁴⁰₁₀₀ x 5 u
= 3 u

Mass of ground pepper transferred from Bag V into Bag U
= 70% x 5 u
= ⁷⁰₁₀₀ x 5 u
= 3.5 u

Mass of ground pepper in Bag U in the end
= 4 u + 2 u + 3.5 u
= 9.5 u

9.5 u = 76 

1 u = 76 ÷ 9.5 = 8

Mass of ground pepper transferred into Bag U
= 2 u + 3.5 u
= 5.5 u
= 5.5 x 8
= 44 kg

Answer(s): 44 kg