Asher had three bags of soya beans, W, X and Y and the mass of each bag of soya beans was in the ratio 1 : 2 : 5. Asher decided to transfer 30% of soya beans from Bag W into Bag X and 60% of soya beans from Bag Y into Bag X. Given that the mass of Bag X was 15.9 kg in the end, how many kilograms of soya beans were transferred into Bag X?

	W	X	Y
Before	1 u	2 u	5 u
Change 1	- 0.3 u	+ 0.3 u
Change 2		+ 3 u	- 3 u
After	0.7 u	5.3 u	2 u

Mass of soya beans transferred from Bag W into Bag X
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.7 u

Mass of soya beans transferred from Bag Y into Bag X
= 60% x 5 u
= ⁶⁰₁₀₀ x 5 u
= 3 u

Mass of soya beans in Bag X in the end
= 2 u + 0.3 u + 3 u
= 5.3 u

5.3 u = 15.9 

1 u = 15.9 ÷ 5.3 = 3

Mass of soya beans transferred into Bag X
= 0.3 u + 3 u
= 3.3 u
= 3.3 x 3
= 9.9 kg

Answer(s): 9.9 kg