Michael had three bags of corn starch, M, N and P and the mass of each bag of corn starch was in the ratio 2 : 1 : 4. Michael decided to transfer 40% of corn starch from Bag M into Bag N and 90% of corn starch from Bag P into Bag N. Given that the mass of Bag N was 54 kg in the end, how many kilograms of corn starch were transferred into Bag N?

	M	N	P
Before	2 u	1 u	4 u
Change 1	- 0.8 u	+ 0.8 u
Change 2		+ 3.6 u	- 3.6 u
After	1.2 u	5.4 u	0.4 u

Mass of corn starch transferred from Bag M into Bag N
= 40% x 2 u
= ⁴⁰₁₀₀ x 2 u
= 1.2 u

Mass of corn starch transferred from Bag P into Bag N
= 90% x 4 u
= ⁹⁰₁₀₀ x 4 u
= 3.6 u

Mass of corn starch in Bag N in the end
= 1 u + 0.8 u + 3.6 u
= 5.4 u

5.4 u = 54 

1 u = 54 ÷ 5.4 = 10

Mass of corn starch transferred into Bag N
= 0.8 u + 3.6 u
= 4.4 u
= 4.4 x 10
= 44 kg

Answer(s): 44 kg