Dylan had three bags of flour, G, H and J and the mass of each bag of flour was in the ratio 4 : 5 : 4. Dylan decided to transfer 20% of flour from Bag G into Bag H and 70% of flour from Bag J into Bag H. Given that the mass of Bag H was 34.4 kg in the end, how many kilograms of flour were transferred into Bag H?
| |
G |
H |
J |
| Before |
4 u |
5 u |
4 u |
| Change 1 |
- 0.8 u |
+ 0.8 u |
|
| Change 2 |
|
+ 2.8 u |
- 2.8 u |
| After |
3.2 u |
8.6 u |
1.2 u |
Mass of flour transferred from Bag G into Bag H
= 20% x 4 u
=
20100 x 4 u
= 3.2 u
Mass of flour transferred from Bag J into Bag H
= 70% x 4 u
=
70100 x 4 u
= 2.8 u
Mass of flour in Bag H in the end
= 5 u + 0.8 u + 2.8 u
= 8.6 u
8.6 u = 34.4
1 u = 34.4 ÷ 8.6 = 4
Mass of flour transferred into Bag H
= 0.8 u + 2.8 u
= 3.6 u
= 3.6 x 4
= 14.4 kg
Answer(s): 14.4 kg
