Elijah had three bags of green beans, C, D and E and the mass of each bag of green beans was in the ratio 1 : 2 : 2. Elijah decided to transfer 10% of green beans from Bag C into Bag D and 60% of green beans from Bag E into Bag D. Given that the mass of Bag D was 26.4 kg in the end, how many kilograms of green beans were transferred into Bag D?

	C	D	E
Before	1 u	2 u	2 u
Change 1	- 0.1 u	+ 0.1 u
Change 2		+ 1.2 u	- 1.2 u
After	0.9 u	3.3 u	0.8 u

Mass of green beans transferred from Bag C into Bag D
= 10% x 1 u
= ¹⁰₁₀₀ x 1 u
= 0.9 u

Mass of green beans transferred from Bag E into Bag D
= 60% x 2 u
= ⁶⁰₁₀₀ x 2 u
= 1.2 u

Mass of green beans in Bag D in the end
= 2 u + 0.1 u + 1.2 u
= 3.3 u

3.3 u = 26.4 

1 u = 26.4 ÷ 3.3 = 8

Mass of green beans transferred into Bag D
= 0.1 u + 1.2 u
= 1.3 u
= 1.3 x 8
= 10.4 kg

Answer(s): 10.4 kg