Sean had three bags of brown rice, C, D and E and the mass of each bag of brown rice was in the ratio 1 : 3 : 5. Sean decided to transfer 10% of brown rice from Bag C into Bag D and 60% of brown rice from Bag E into Bag D. Given that the mass of Bag D was 48.8 kg in the end, how many kilograms of brown rice were transferred into Bag D?

	C	D	E
Before	1 u	3 u	5 u
Change 1	- 0.1 u	+ 0.1 u
Change 2		+ 3 u	- 3 u
After	0.9 u	6.1 u	2 u

Mass of brown rice transferred from Bag C into Bag D
= 10% x 1 u
= ¹⁰₁₀₀ x 1 u
= 0.9 u

Mass of brown rice transferred from Bag E into Bag D
= 60% x 5 u
= ⁶⁰₁₀₀ x 5 u
= 3 u

Mass of brown rice in Bag D in the end
= 3 u + 0.1 u + 3 u
= 6.1 u

6.1 u = 48.8 

1 u = 48.8 ÷ 6.1 = 8

Mass of brown rice transferred into Bag D
= 0.1 u + 3 u
= 3.1 u
= 3.1 x 8
= 24.8 kg

Answer(s): 24.8 kg