Jenson had three bags of brown rice, U, V and W and the mass of each bag of brown rice was in the ratio 1 : 5 : 5. Jenson decided to transfer 20% of brown rice from Bag U into Bag V and 60% of brown rice from Bag W into Bag V. Given that the mass of Bag V was 65.6 kg in the end, how many kilograms of brown rice were transferred into Bag V?

	U	V	W
Before	1 u	5 u	5 u
Change 1	- 0.2 u	+ 0.2 u
Change 2		+ 3 u	- 3 u
After	0.8 u	8.2 u	2 u

Mass of brown rice transferred from Bag U into Bag V
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.8 u

Mass of brown rice transferred from Bag W into Bag V
= 60% x 5 u
= ⁶⁰₁₀₀ x 5 u
= 3 u

Mass of brown rice in Bag V in the end
= 5 u + 0.2 u + 3 u
= 8.2 u

8.2 u = 65.6 

1 u = 65.6 ÷ 8.2 = 8

Mass of brown rice transferred into Bag V
= 0.2 u + 3 u
= 3.2 u
= 3.2 x 8
= 25.6 kg

Answer(s): 25.6 kg