Zeph had three bags of soya beans, H, J and K and the mass of each bag of soya beans was in the ratio 3 : 2 : 3. Zeph decided to transfer 30% of soya beans from Bag H into Bag J and 80% of soya beans from Bag K into Bag J. Given that the mass of Bag J was 47.7 kg in the end, how many kilograms of soya beans were transferred into Bag J?

	H	J	K
Before	3 u	2 u	3 u
Change 1	- 0.9 u	+ 0.9 u
Change 2		+ 2.4 u	- 2.4 u
After	2.1 u	5.3 u	0.6 u

Mass of soya beans transferred from Bag H into Bag J
= 30% x 3 u
= ³⁰₁₀₀ x 3 u
= 2.1 u

Mass of soya beans transferred from Bag K into Bag J
= 80% x 3 u
= ⁸⁰₁₀₀ x 3 u
= 2.4 u

Mass of soya beans in Bag J in the end
= 2 u + 0.9 u + 2.4 u
= 5.3 u

5.3 u = 47.7 

1 u = 47.7 ÷ 5.3 = 9

Mass of soya beans transferred into Bag J
= 0.9 u + 2.4 u
= 3.3 u
= 3.3 x 9
= 29.7 kg

Answer(s): 29.7 kg