Peter had three bags of soya beans, J, K and L and the mass of each bag of soya beans was in the ratio 4 : 5 : 4. Peter decided to transfer 30% of soya beans from Bag J into Bag K and 80% of soya beans from Bag L into Bag K. Given that the mass of Bag K was 37.6 kg in the end, how many kilograms of soya beans were transferred into Bag K?

	J	K	L
Before	4 u	5 u	4 u
Change 1	- 1.2 u	+ 1.2 u
Change 2		+ 3.2 u	- 3.2 u
After	2.8 u	9.4 u	0.8 u

Mass of soya beans transferred from Bag J into Bag K
= 30% x 4 u
= ³⁰₁₀₀ x 4 u
= 2.8 u

Mass of soya beans transferred from Bag L into Bag K
= 80% x 4 u
= ⁸⁰₁₀₀ x 4 u
= 3.2 u

Mass of soya beans in Bag K in the end
= 5 u + 1.2 u + 3.2 u
= 9.4 u

9.4 u = 37.6 

1 u = 37.6 ÷ 9.4 = 4

Mass of soya beans transferred into Bag K
= 1.2 u + 3.2 u
= 4.4 u
= 4.4 x 4
= 17.6 kg

Answer(s): 17.6 kg