Zane had three bags of peppercorns, F, G and H and the mass of each bag of peppercorns was in the ratio 1 : 2 : 4. Zane decided to transfer 30% of peppercorns from Bag F into Bag G and 70% of peppercorns from Bag H into Bag G. Given that the mass of Bag G was 30.6 kg in the end, how many kilograms of peppercorns were transferred into Bag G?

	F	G	H
Before	1 u	2 u	4 u
Change 1	- 0.3 u	+ 0.3 u
Change 2		+ 2.8 u	- 2.8 u
After	0.7 u	5.1 u	1.2 u

Mass of peppercorns transferred from Bag F into Bag G
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.7 u

Mass of peppercorns transferred from Bag H into Bag G
= 70% x 4 u
= ⁷⁰₁₀₀ x 4 u
= 2.8 u

Mass of peppercorns in Bag G in the end
= 2 u + 0.3 u + 2.8 u
= 5.1 u

5.1 u = 30.6 

1 u = 30.6 ÷ 5.1 = 6

Mass of peppercorns transferred into Bag G
= 0.3 u + 2.8 u
= 3.1 u
= 3.1 x 6
= 18.6 kg

Answer(s): 18.6 kg