Warren had three bags of green beans, X, Y and Z and the mass of each bag of green beans was in the ratio 4 : 2 : 3. Warren decided to transfer 30% of green beans from Bag X into Bag Y and 60% of green beans from Bag Z into Bag Y. Given that the mass of Bag Y was 15 kg in the end, how many kilograms of green beans were transferred into Bag Y?

	X	Y	Z
Before	4 u	2 u	3 u
Change 1	- 1.2 u	+ 1.2 u
Change 2		+ 1.8 u	- 1.8 u
After	2.8 u	5 u	1.2 u

Mass of green beans transferred from Bag X into Bag Y
= 30% x 4 u
= ³⁰₁₀₀ x 4 u
= 2.8 u

Mass of green beans transferred from Bag Z into Bag Y
= 60% x 3 u
= ⁶⁰₁₀₀ x 3 u
= 1.8 u

Mass of green beans in Bag Y in the end
= 2 u + 1.2 u + 1.8 u
= 5 u

5 u = 15 

1 u = 15 ÷ 5 = 3

Mass of green beans transferred into Bag Y
= 1.2 u + 1.8 u
= 3 u
= 3 x 3
= 9 kg

Answer(s): 9 kg