Jack had three bags of green beans, N, P and Q and the mass of each bag of green beans was in the ratio 5 : 1 : 3. Jack decided to transfer 20% of green beans from Bag N into Bag P and 60% of green beans from Bag Q into Bag P. Given that the mass of Bag P was 22.8 kg in the end, how many kilograms of green beans were transferred into Bag P?

	N	P	Q
Before	5 u	1 u	3 u
Change 1	- 1 u	+ 1 u
Change 2		+ 1.8 u	- 1.8 u
After	4 u	3.8 u	1.2 u

Mass of green beans transferred from Bag N into Bag P
= 20% x 5 u
= ²⁰₁₀₀ x 5 u
= 4 u

Mass of green beans transferred from Bag Q into Bag P
= 60% x 3 u
= ⁶⁰₁₀₀ x 3 u
= 1.8 u

Mass of green beans in Bag P in the end
= 1 u + 1 u + 1.8 u
= 3.8 u

3.8 u = 22.8 

1 u = 22.8 ÷ 3.8 = 6

Mass of green beans transferred into Bag P
= 1 u + 1.8 u
= 2.8 u
= 2.8 x 6
= 16.8 kg

Answer(s): 16.8 kg