Reggie had three bags of brown rice, M, N and P and the mass of each bag of brown rice was in the ratio 3 : 2 : 4. Reggie decided to transfer 20% of brown rice from Bag M into Bag N and 80% of brown rice from Bag P into Bag N. Given that the mass of Bag N was 34.8 kg in the end, how many kilograms of brown rice were transferred into Bag N?

	M	N	P
Before	3 u	2 u	4 u
Change 1	- 0.6 u	+ 0.6 u
Change 2		+ 3.2 u	- 3.2 u
After	2.4 u	5.8 u	0.8 u

Mass of brown rice transferred from Bag M into Bag N
= 20% x 3 u
= ²⁰₁₀₀ x 3 u
= 2.4 u

Mass of brown rice transferred from Bag P into Bag N
= 80% x 4 u
= ⁸⁰₁₀₀ x 4 u
= 3.2 u

Mass of brown rice in Bag N in the end
= 2 u + 0.6 u + 3.2 u
= 5.8 u

5.8 u = 34.8 

1 u = 34.8 ÷ 5.8 = 6

Mass of brown rice transferred into Bag N
= 0.6 u + 3.2 u
= 3.8 u
= 3.8 x 6
= 22.8 kg

Answer(s): 22.8 kg