Jeremy had three bags of soya beans, T, U and V and the mass of each bag of soya beans was in the ratio 1 : 1 : 1. Jeremy decided to transfer 30% of soya beans from Bag T into Bag U and 60% of soya beans from Bag V into Bag U. Given that the mass of Bag U was 9.5 kg in the end, how many kilograms of soya beans were transferred into Bag U?

	T	U	V
Before	1 u	1 u	1 u
Change 1	- 0.3 u	+ 0.3 u
Change 2		+ 0.6 u	- 0.6 u
After	0.7 u	1.9 u	0.4 u

Mass of soya beans transferred from Bag T into Bag U
= 30% x 1 u
= ³⁰₁₀₀ x 1 u
= 0.7 u

Mass of soya beans transferred from Bag V into Bag U
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Mass of soya beans in Bag U in the end
= 1 u + 0.3 u + 0.6 u
= 1.9 u

1.9 u = 9.5 

1 u = 9.5 ÷ 1.9 = 5

Mass of soya beans transferred into Bag U
= 0.3 u + 0.6 u
= 0.9 u
= 0.9 x 5
= 4.5 kg

Answer(s): 4.5 kg