Elijah had three bags of barley, K, L and M and the mass of each bag of barley was in the ratio 3 : 2 : 5. Elijah decided to transfer 20% of barley from Bag K into Bag L and 80% of barley from Bag M into Bag L. Given that the mass of Bag L was 39.6 kg in the end, how many kilograms of barley were transferred into Bag L?
| |
K |
L |
M |
| Before |
3 u |
2 u |
5 u |
| Change 1 |
- 0.6 u |
+ 0.6 u |
|
| Change 2 |
|
+ 4 u |
- 4 u |
| After |
2.4 u |
6.6 u |
1 u |
Mass of barley transferred from Bag K into Bag L
= 20% x 3 u
=
20100 x 3 u
= 2.4 u
Mass of barley transferred from Bag M into Bag L
= 80% x 5 u
=
80100 x 5 u
= 4 u
Mass of barley in Bag L in the end
= 2 u + 0.6 u + 4 u
= 6.6 u
6.6 u = 39.6
1 u = 39.6 ÷ 6.6 = 6
Mass of barley transferred into Bag L
= 0.6 u + 4 u
= 4.6 u
= 4.6 x 6
= 27.6 kg
Answer(s): 27.6 kg
