Julian had three bags of soya beans, N, P and Q and the mass of each bag of soya beans was in the ratio 2 : 3 : 3. Julian decided to transfer 30% of soya beans from Bag N into Bag P and 90% of soya beans from Bag Q into Bag P. Given that the mass of Bag P was 12.6 kg in the end, how many kilograms of soya beans were transferred into Bag P?

	N	P	Q
Before	2 u	3 u	3 u
Change 1	- 0.6 u	+ 0.6 u
Change 2		+ 2.7 u	- 2.7 u
After	1.4 u	6.3 u	0.3 u

Mass of soya beans transferred from Bag N into Bag P
= 30% x 2 u
= ³⁰₁₀₀ x 2 u
= 1.4 u

Mass of soya beans transferred from Bag Q into Bag P
= 90% x 3 u
= ⁹⁰₁₀₀ x 3 u
= 2.7 u

Mass of soya beans in Bag P in the end
= 3 u + 0.6 u + 2.7 u
= 6.3 u

6.3 u = 12.6 

1 u = 12.6 ÷ 6.3 = 2

Mass of soya beans transferred into Bag P
= 0.6 u + 2.7 u
= 3.3 u
= 3.3 x 2
= 6.6 kg

Answer(s): 6.6 kg